Question

prove it by Thales theorem :-AX/BX=AY/CY​

Answer 1

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Given,

∠AXY=∠AYX

So,AX=AY [Sides opposite to equal angles are equal.]

Also, from BPT we have

BX/AX=CY/AY

Thus,

AX+BX=AY+CY

So,AB=AC

Therefore, ΔABC is an isosceles triangle.