Question

prove it cotA - tanA = 2cot2A

Answer 1

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$\bold{\underline{Question-}}$

prove it cotA - tanA = 2cot2A



$\bold{\underline{Answer-}}$


LHS = cotA - tanA

$= \frac{cos \: a}{sin \: a} - \frac{sin \: a}{cos \: a} \\ \\ = \frac{ {cos}^{2} a - {sin}^{2}a }{sin \: a \: cos \: a} \\ \\ \\ = \frac{cos \: 2a}{sin \: a \: cos \: a}$

multiplying with 2

$= \frac{2cos \: 2a}{2sin \: a \: cos \: a} \\ \\ \\ = \frac{2cos2a}{sin2a} \\ \\ \\ = 2cot2a$


LHS = RHS

Answer 2

Step-by-step explanation:

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