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1)as two chord are equal so the line ol and om is equal as both intercept on chord so form 90 degree
angle olm=angle oml ( as both side are equal so it's opposite angle are equal)
2 )angle Alm=angle cml( opposite angle ) as two equal chord intersect each other
I try hope it helps you
Anonymous:
Sorry dude! I need answer with proper explanation...
Answered by
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As perpendicular drawn from centre bisects the chord
So here At L and M chords are bisected
So OL and OM is perpendicular to AB and CD respectively
NOW in triangle OLB AND ODM
OB = OD ( RADIUS)
<OLB = <OMD = 90
LB = MD ( as AB = CD and L and M are mid points )
So SAS
THEREFORE OL = OM
IN OLM
OL = OM
SO it becomes isosceles
now angles opp.are equal to equal sides
So <OLM = <OML
<OLB = 90
<OMD = 90
<OLM = <OML
AS <ALM + <MLO.+ <OLB = 180( LINEAR)
ALSO <CML + <OML + <OMD = 180
AS MLO = OML
OLB = OMD = 90
HENCE <ALM = <CML
So here At L and M chords are bisected
So OL and OM is perpendicular to AB and CD respectively
NOW in triangle OLB AND ODM
OB = OD ( RADIUS)
<OLB = <OMD = 90
LB = MD ( as AB = CD and L and M are mid points )
So SAS
THEREFORE OL = OM
IN OLM
OL = OM
SO it becomes isosceles
now angles opp.are equal to equal sides
So <OLM = <OML
<OLB = 90
<OMD = 90
<OLM = <OML
AS <ALM + <MLO.+ <OLB = 180( LINEAR)
ALSO <CML + <OML + <OMD = 180
AS MLO = OML
OLB = OMD = 90
HENCE <ALM = <CML
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