prove it in triangle
angle C=angle3B=angle2(A+B)
Answers
Answered by
4
A+B+C=180
A+B=180-C
{A+B=180-3B}
3B=2(180-3B)
3B=360-6B
9B=360
B=40
C=3B
C=3×40
C=120
A+B+C=180
A+120+40=180
A=180-160
A=20
A=20, B=40, C=120
hope its help u
A+B=180-C
{A+B=180-3B}
3B=2(180-3B)
3B=360-6B
9B=360
B=40
C=3B
C=3×40
C=120
A+B+C=180
A+120+40=180
A=180-160
A=20
A=20, B=40, C=120
hope its help u
Answered by
0
A+B+C=180
A+B=180-C
{A+B=180-3B}
3B=2(180-3B)
3B=360-6B
9B=360
B=40
C=3B
C=3×40
C=120
A+B+C=180
A+120+40=180
A=180-160
A=20
A=20, B=40, C=120
hope its help u
A+B=180-C
{A+B=180-3B}
3B=2(180-3B)
3B=360-6B
9B=360
B=40
C=3B
C=3×40
C=120
A+B+C=180
A+120+40=180
A=180-160
A=20
A=20, B=40, C=120
hope its help u
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