Question

prove it in very simple language.

Answer 1

In triangle QTR,
‹TRS=‹QTR+‹TQR[ext. ‹ property]
=1/2‹PRS=‹QTR+1/2‹PQR[QT AND RT bisect ‹Q and ‹PRS]-----(1)
In triangle PQR,
‹PRS=‹QPR+‹PQR
=1/2‹PRS=1/2‹QPR+1/2PQR
=‹QTR+1/2‹PQR=1/2‹QPR+1/2‹PQR[using (1)]
=1/2‹QPR

Hope this helps you.

Answer 2

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answer in attachment...

hope it will help you ✌️✌️