Prove it pleeease 25 points!!!!! Wrong answer will be reported please
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Given cos5θ=0
cos4θcosθ−sin4θsinθ=0
(2cos
2
2θ−1)cosθ−2sin2θcos2θsinθ=0
cosθ[2cos
2
2θ−1−4sin
2
θcos2θ]=0
cosθ[4cos
2
2θ−2cos2θ−1]=0
⇒cosθ=0 or 4cos
2
2θ−2cos2θ−1=0
⇒cosθ=0 or cos2θ=
4
1±
5
⇒cos
2
θ=
8
5±
5
⇒(8cos
2
θ−5)
2
=5
⇒64cos
4
θ−80cos
2
θ+20=0
⇒64cos
4
θ−80cos
2
θ+1625=1605
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Step-by-step explanation:
The correct answer is 6 Thetha.......
please mark as brainliest
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