Question

prove it plz... by using multiple or submultiple angles (trigo)
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Answer 1

Answer:

Please find the attachment

Step-by-step explanation:

Hope this helps you

Answer 2

Answer:

LHS=

$\sqrt{ \frac{1 + \sin(x) }{1 - \sin(x) } }$

use

$1 + \sin(x)$

$= { (sin( \frac{x}{2} ))}^{2} + { (cos( \frac{x}{2} )) }^{2} + sinx = ( {( \cos( \frac{x}{2} ) + \sin( \frac{x}{2} ) ) }^{2}$

$similarly \: \: \: \: \: \: \: \\ \\ \\ \: \: \: { (sin( \frac{x}{2} ))}^{2} + { (cos( \frac{x}{2} )) }^{2} + \\ - sinx = ( {( \cos( \frac{x}{2} ) - \sin( \frac{x}{2} ) ) }^{2}$

then remove square root

then multiply numerator and denominator by cosx

then take 1 as

$\tan( \frac{\pi}{4} )$

u will get the answer