prove it plz with formulas
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Answered by
4
sin2A/1+cos2A
= (2sinAcosA)/(1+2cos^(2)A-1)
=(2sinAcosA)/ 2cos^(2)A
= 2sinA/2cosA
=tanA
= (2sinAcosA)/(1+2cos^(2)A-1)
=(2sinAcosA)/ 2cos^(2)A
= 2sinA/2cosA
=tanA
Anonymous:
But the question is asking for tan A not 2 tan A
Answered by
2
As per the Trigonometric Identities,
sin 2A = 2.sin A .cos A
1 + cos 2A = 2.
=
= tan A
It's so simple.
sin 2A = 2.sin A .cos A
1 + cos 2A = 2.
=
= tan A
It's so simple.
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