Math, asked by ashish008242, 6 hours ago

prove it
root under (2cos theta)²+sin²theta = 3cos²theta+1

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Answers

Answered by mira12313

1

Answer:

LHS=tanθ−cotθ

=cosθsinθ−sinθcosθ

=sinθcosθsin2θ−cos2θ

=sinθcosθsin2θ−(1−sin2θ)

=sinθcosθ2sin2θ−1

=RHS

Hence proved

Step-by-step explanation:

please as brianlist

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