Question

prove it :
sec^4 A - sec^2 A = tan^4A + Tan^2A

Answer 1

Answer:

Solution:

Given

LHS = tan⁴A+tan²A

= (tan²A)²+tan²A

= tan²A(tan²A+1)

= tan²Asec²A

________________________

*/ By Trigonometric identity:

1+tan²A = sec²A

Or

tan²A = sec²A-1*/

________________________

= (sec²A-1)sec²A

= sec⁴A-sec²A

= RHS

Therefore,

tan⁴A+tan²A = sec⁴A-sec²A

HOPE IT HELP YOU :)

Answer 2

Answer:

sec  4 A−sec  2 A=sec  2 A(sec  2 A−1)

=(1+tan  2 A)(1+tan  2 A−1)

=tan  2 A+ tan 4 A

Step-by-step explanation: