Question

Prove it.
sin^6o+cos^6o =1-3sin^2o*cos^2o. ​

Answer 1

Answer:

proved

Step-by-step explanation:

Sin A+ Cos A

[Sin²A]³+ [Cos²]³

(a+b) (a²-ab+b²)]

[... (a³+b³)=

(Cos² A+ Sin²A) (Cos¹ A - Cos2 A.Sin² A+ Siz → (Sin¹ A+ Cos¹ A) - Sin²A.Cos² A

(Sin² A+ Cos² A)² - 2Sin²A.Cos2 A - Sin²A.C

[.. Cos²A+Sin²A=1]

→ 1-3Sin² A.Cos² A

[Hence, proved]

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