Question

Prove it, solve it quick​

Answer 1

Answer:

Exponential laws:-

$\frac{ {a}^{m} }{ {a}^{n} } = {a}^{m - n}$

Applying the law here :-

$\frac{( {l})^{ \frac{3}{2} } }{l} + \frac{( {m)}^{ \frac{2}{3} } }{ m} \\ {l}^{ (\frac{3}{2} - 1) } + {m}^{( \frac{2}{3} - 1)} \\ {l}^{ (\frac{3 - 2}{2}) } + {m}^{( \frac{2 - 3}{3}) } \\ {l}^{( \frac{1}{2}) } + {m}^{( \frac{ - 1}{3} )} \\ \sqrt{l} + </em></strong><strong><em>1</em></strong><strong><em>/</em></strong><strong><em>\sqrt[3]{m} = </em></strong><strong><em>RHS</em></strong><strong><em>$

Hence proved that LHS = RHS

=====================

Answer 2

Answer:

here is your answer

plz mark me as brainliest