prove it that answer is 54km/hr
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Answer:
option (3) 30 kmph
Explanation:
greatest speed is achieved when the car will be at the end of its acceleration time, and moves with constant speed, v = 60kmph.
let the respective time slots for each period be t:8t:t
let acceleration be a
thus if initial velocity = 0
then using first equation of motion:
v = 60 = a.t ______eq(1)
distance travelled while this time: s1 = 1/2 a.t2 = 1/2 60t = 30t (from eq(1) )
distance traveled in next constant sped slot:
s2 = 60x8t = 240t (using ratio here t= 8t)
let retarding be at rate r
thus using first eq of motion:
60 = rt
distance travelled in this slot:
s3 = (60)2/2r = 30t
thus average speed = total distance / total time = (30t+240t+30t)/10t = 30 kmph
plz mar brainliest plzzz.
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