Math, asked by Krity10, 7 months ago

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Answered by NagendraSaiN
1

Answer:

Step by Step

RHS:

  • sin 4x.sin 8x

sin a.sinb =  \frac{1}{2} (cos(a - b) - cos(a + b))

With this the above equation becomes

  •  \frac{1}{2}( \cos(4x)  -  \cos(12x)
  •  \cos(2x)  = 2 ( { \cos(x) }^{2}  - 1)

after simplyfying this we get LHS

Answered by ginneman47
1

Answer:

here is the explanation to the given question

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