Question

Prove it ... yooo brooos

Answer 1

Answer:

We All Know That

sin³A = (3sinA - sin3A)/4

cos³A = (3cosA + cos3A)/4

Getting Back To The Question

(sinA - 2sin³A)/(2cos³A - cosA) = tanA

Putting The Value of sin³A and cos³A in LHS

We Get,

(2sinA - 3sinA + sin3A)/(3cosA + cos3A - 2cosA)

= (sin3A - sinA)/(cos3A + cosA)

Now Using the sinC - sinD and cosC + cosD Formula

sinC - sinD = 2cos(C+D)/2*sin(C-D)/2

cosC + cosD = 2cos(C+D)/2*cos(C-D)/2

= (2cos(3A+A)/2*sin(3A-A)/2) / (2cos(3A+A)/2*cos(3A-A)/2)

= 2cos2A*sinA/2cos2A*sinA

= sinA/cosA

= tanA

LHS = RHS

Hence Proved.... ^_^

Answer 2

Answer:

The answer above me is correct

Step-by-step explanation: