prove kinetic energy = mgh
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Answered by
1
Hey User!!!
Its seems that your given statement is wrong !!!
So why to prove it ?????
ACCORDING TO PHYSICS ,, KINETIC ENERGY IS ALWAYS EQUAL TO = 1÷2×MASS×VELOCITY SQUARE...
AND POTENTIAL ENERGY IS ALWAYS EQUAL TO = MASS ×GRAVITY×HEIGHT .
SO, PLZ CORRECT YOUR STATEMENT IN THE GIVEN QUESTON...
HOPE IT HELPS U
THANKS.
Its seems that your given statement is wrong !!!
So why to prove it ?????
ACCORDING TO PHYSICS ,, KINETIC ENERGY IS ALWAYS EQUAL TO = 1÷2×MASS×VELOCITY SQUARE...
AND POTENTIAL ENERGY IS ALWAYS EQUAL TO = MASS ×GRAVITY×HEIGHT .
SO, PLZ CORRECT YOUR STATEMENT IN THE GIVEN QUESTON...
HOPE IT HELPS U
THANKS.
loudu:
shut up ok
Answered by
4
Heya,
Seems question is wrng.
I guess the question is to Prove KE = 1/2mv^2
If yes,
Then:-
Kinetic Energy:-
The kinetic energy of a moving body is measured by the amount of work it can do before coming to rest.
Consider a body of mass 'm' moving with an initial velocity 'u'. When a force 'F' is applied on it , which displaces the object through a distance 's' and it's final velocity changes to 'v' and it produces an acceleration 'a'.
We know that,
v^2 - u^2 = 2as
s = v^2 - u^2/2a
Work done(W) = F × s
We know from Newton's second law of motion F = ma
W = ma × (v^2 - u^2/2a) (or)
W = 1/2 m(v^2 - u^2)
When the object starts from rest then it's initial velocity u = 0
Hence,
W = 1/2mv^2
This work done is stored in a form of KE
Therefore,
KE = 1/2 mv^2
Hope my answer helps you :)
Regards,
Shobana
Seems question is wrng.
I guess the question is to Prove KE = 1/2mv^2
If yes,
Then:-
Kinetic Energy:-
The kinetic energy of a moving body is measured by the amount of work it can do before coming to rest.
Consider a body of mass 'm' moving with an initial velocity 'u'. When a force 'F' is applied on it , which displaces the object through a distance 's' and it's final velocity changes to 'v' and it produces an acceleration 'a'.
We know that,
v^2 - u^2 = 2as
s = v^2 - u^2/2a
Work done(W) = F × s
We know from Newton's second law of motion F = ma
W = ma × (v^2 - u^2/2a) (or)
W = 1/2 m(v^2 - u^2)
When the object starts from rest then it's initial velocity u = 0
Hence,
W = 1/2mv^2
This work done is stored in a form of KE
Therefore,
KE = 1/2 mv^2
Hope my answer helps you :)
Regards,
Shobana
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