Question

prove law of conservation of momentum​

Answer 1

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YOUR ANSWER IS AS FOLLOWS...............
What’s the proof of conservation of momentum?
For linear momentum , you prove it using the Newton’s Third Law .

So , Newton’s Third Law says that F1on2=−F2on1.

Now , both the action and reaction occur simultaneously , i.e. the forces act for the same amount of time .

F=m×a.

Thus ,

m1∗a1=−m2∗a2

m1×v1−u1Δt1=m2×v2−u2Δt2.

Now , since both forces act for the same amount of time ,

Δt1=Δt2.

Thus cancelling the Δt′sout of the previous equation ,

m1(v1−u1)=−m2(v2−u2)=m2(u2−v2)

m1v1−m1u1=m2u2−m2v2.

Rearranging ,

m1v1+m2v2=m1u1+m2u2.

Thus you get the required result ,

m1u1+m2u2=m1v1+m2v2.





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THANK YOU......

Answer 2

Hi Mate,

→momentum of a system always remain constant.

→sum of momentum of the bodyies / particles of a system is equal to the total momentum of the system.

→when two bodies of masses $m_{1}$ and $m_{2}$ moving with initial velocity $v_{2}$ and $v_{2}$ respectively along a straight line path collide with each other for a short time. their velocity becomes $V_{1}, V_{2}$.

→according to Newton's third law

$F_{ab}= -F_{ba}$

→m1(v-u)/t = -m2(v2-u2)/t
=m1v1-m1u1= -m2v2+m2v2
=m1u1+m2v2=m1v1+m2v2
=initial momentum before collision=final momentum after collision.

=>Sorry mate, the answer looks like very congested.

Hope This Helps You......