Question

prove lhs equal to rhs

Answer 1

Hiii. ....friends

The answer is here,

$= > \: cotx - tanx$

$= > \: \frac{cosx}{sinx} - \frac{sinx}{cosx}$

$= > \: \frac{ {cos}^{2}x - {sin}^{2} x}{sinx.cosx}$

We know that,

${sin}^{2} x + {cos}^{2} x = 1$

$= > \: {sin}^{2} x = 1 - {cos}^{2} x$

$= > \: \frac{ {cos}^{2} x - 1 + {cos}^{2} x}{sinx \times cosx}$

$= > \: \frac{2 {cos}^{2}x - 1 }{sinx.cosx}$

Hence, LHS = RHS.

Thus proved .

:-)Hope it helps u.

Answer 2

hope it help you dear.......