prove LHS is equal to rhs
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LHS , TERM .
[cos A/1 -tan A ] - [sin²A / cos A -sin A ]
REMEMBER ⇒ tan A = sin A / cos A
⇒ [cos A / 1 - (sin A / cos A )] - [ sin ² A / cos A - sin A ]
⇒ [cos A × cos A / cos A - sin A ] - [ sin ²A / cos A - sin A ]
⇒ cos ² A - sin ² A / cos A - sin A
⇒ ( cos A - sin A ) ( cos A + sin A ) / cos A - sin A
⇒ cos A + sin A
⇒ LHS = RHS ....
HENCE PROVED ..
Step-by-step explanation: hope this will help u mate , need feed back plz ,
itz akansha
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