Prove LHS=RHS , 1+cot^2A/1+cosecA=cosecA.
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Answer:
LHS= 1 + cot^2A/1+cosecA
=(1+cosecA + cot^2A)/1+cosecA
{By using basic trigonometric theorem cot^2A = cosec^2A - 1}
=(1+cosecA + cosec^2A - 1)/(1+cosecA)
=(cosecA + cosec^2A)/(1+cosecA)
=[cosecA (1+cosecA)]/(1+cosecA)
{Cancelling 1+cosecA}
=cosecA
Step-by-step explanation:
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