prove lhs=Rhs
please do it
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I've simply brought (3x−9)/(x2−9) over to the LHS, resulting in the equation (x2−3x)/(x2−9)+(3x−9)/(x2−9)=1 , which gives me (x2−9)/(x2−9)=1.(LHS = RHS)
Furthermore , after which I'm integrating (x2−3x)/(x2−9) by doing the following:
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