prove( log 5to base 5 )(log4to base 9)(log2 to base 3) = 1
Answers
Answered by
1
Answer:
Step-by-step explanation:
Answer should be 2ab-1
By BASE CHANGE RULE
Log5(base)4 become log5÷log4
Similarly log6÷log5
Multiply both we get
(Log6×log5)÷(log5×log4)=a×b
log6÷log4=a×b
Log(3×2)÷log4=a×b
(log3+log2)÷2log2=a×b
log3÷2log2+1/2=a×b
Log3÷2log2=ab-1/2
1/2log3÷log2=( 2ab-1)/2
By base change RULE
Log3(base)2=(2ab-1)2/2
Log3(base)2=2ab-1
Answered by
0
♦ Pls refer the attachment for your solution.
Thank you! ✨❤️
Attachments:
Similar questions