prove logab*logbc*logca =1
Answers
Answered by
0
Answer:
Step-by-step explanation:
Logab => log b to base a.
Logab = Logxb/logxa => Log b to base x / log a to base x (Where x is a
constant)
similarly
logbc = logxc/logxb
logca = logxa/logxc
=> Logxb/logxa * logxc/logxb * logxa/logxc
= 1
Similar questions