Prove logically that the diagonal of a rectangle are equal.
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Answered by
1
Proof :
ABCD is a rectangle and AC and BD
are it's diagonals.
We want know AC = BD
ABCD is a rectangle , means ABCD is a
parallelogram with all its angles equal
to right angle.
Consider the triangles ∆ABC and ∆BAD
AB = BA ( Common )
<B = <A = 90° [ Each angle of rectangle ]
BC = AD [ Opposite sides of the rectangle]
Therefore ,
∆ABC congruent to ∆BAD
=> AC = BD
or the diagonals of a rectangle are
equal .
•••••
ABCD is a rectangle and AC and BD
are it's diagonals.
We want know AC = BD
ABCD is a rectangle , means ABCD is a
parallelogram with all its angles equal
to right angle.
Consider the triangles ∆ABC and ∆BAD
AB = BA ( Common )
<B = <A = 90° [ Each angle of rectangle ]
BC = AD [ Opposite sides of the rectangle]
Therefore ,
∆ABC congruent to ∆BAD
=> AC = BD
or the diagonals of a rectangle are
equal .
•••••
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Answered by
0
Let ABCD be a rectangle.
Then AC and BD are the diagonals.
To Prove: AC=BD
Proof : In △ABC and △ABD
∠ABC = ∠BAD [90⁰]
BC=AD [Opp. Sides]
AB=AB [Common side]
△ABC ≅ △ABD[SAS]
AC=BD
Hence proved✅.
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