Prove m(A.B)=(mA).B=A.(mB)=(A.B)m where m is scalar and A & B are vectors
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Step-by-step explanation:
a.b=a.c
a.b−a.c=0
a.(b−c)=0
∣a∣.∣b−c∣cosθ=0
⇒∣a∣
=0 also cosθ
=0
⇒a.b=a.c
=0
⇒∣b−c∣=0
∴b=c
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