Prove mathematically that Work done In a cyclic process is zero?
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friend! 1st you must understand that cyclic process is a sequence of events which leaves the system in the same state as in the beginning!
When a system undergoes cyclic process--> Both the initial internal energy (U) & the final internal energy remains the same!
So change in internal energy (ΔU)=0. Apply this in the formula of 1st law of thermodynamics (ΔU=q+W).--> W=q
I hope the above helps and moreover plz verify your question once again!
When a system undergoes cyclic process--> Both the initial internal energy (U) & the final internal energy remains the same!
So change in internal energy (ΔU)=0. Apply this in the formula of 1st law of thermodynamics (ΔU=q+W).--> W=q
I hope the above helps and moreover plz verify your question once again!
Anonymous:
I thought brainly was a platform to ask even the silliest of doubts...wanna verify the question after answering it??
lol, chuck it! I just wanted to be more accurate :P
Haha smarty
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