Math, asked by hanumanrana24, 10 months ago

prove of a,b,c are in continued proportion
a2+b2 b(a+c)
-----------. = --------------
b(a+c). ​b2+c2​

Answers

Answered by manojatindia
8

Step-by-step explanation:

a, b and c are the continued proportion

a : b = b : c

⇒ a/b = b/c

⇒ b2 = ac

Now a/c = a2 + b2/b2 + c2

⇒ a(b2 + c2) = c(a2 + b2)

L.H.S. = a(b2 + c2) ⇒ a(ac + c2) ⇒ ac(a + c)

R.H.S. = c(a2 + b2) ⇒ c(a2 + ac) ⇒ ac(a + c)

L.H.S. = R.H.S. Hence proved.

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