Math, asked by ishavarunxzxx, 1 month ago

prove of hermition matrix​

Answers

Answered by Anonymous
0

 \huge \sf     {\orange{\underline{\purple{\underline{Answer:-}}}}}

■》 In mathematics, a Hermitian matrix (or self-adjoint matrix) is a complex square matrix that is equal to its own conjugate transpose—that is, the element in the i-th row and j-th column is equal to the complex conjugate of the element in the j-th row and i-th column, for all indices i and j:

{\displaystyle A{\text{ Hermitian}}\quad \iff \quad a_{ij}={\overline {a}}_{ji}}

or in matrix form:

{\displaystyle A{\text{ Hermitian}}\quad \iff \quad A={\overline {A^{\mathsf {T}}}}.}

Hermitian matrices can be understood as the complex extension of real symmetric matrices.

If the conjugate transpose of a matrix {\displaystyle A} is denoted by {\displaystyle A^{\mathsf {H}}}, then the Hermitian property can be written concisely as

{\displaystyle A{\text{ Hermitian}}\quad \iff \quad A=A^{\mathsf {H}}}

Answered by susmita2891
0

 \huge \color{red} \boxed{\colorbox{pink}{Refer\:to\:the\: attachment}}

Attachments:
Similar questions