Prove : Opposite angles of a cyclic quadrilateral are supplementary
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Prove the opposite angles of a cyclic quadrilateral are supplementary.
Step-by-step explanation:
Given : A cyclic quadrilateral ABCD.
To Prove :
angle A + angle C = 180°
angle B + angle D = 180°
Construction : Let O be the center of the circle. Join O to B and D. Then let the angle subtended by the minor arc and the major arc at the centre be x° and y° tespectively.
Proof : x° = 2 angle C ( angle at the centre theorem) ------ eqn 1
y° =2 angle A ------- eqn 2
Adding eqn 1 and 2 we get
x° + y° = 2 angle C + 2 angle A ------- eqn 3
But x° + y° = 360°
From eqn 3 and 4 we get,
2 angle C + 2 angle A = 360°
=> angle C + angle A = 180°
But we know that angle sum property of quadrilateral.
angleA + angle B + angle C + angle S = 360°
angle B + angle D + 180° = 360°
angle B + angle D = 360° - 180°
angle B + angle D = 180°
Hence proved.