Question

Prove p(q+r)=(pq)+(pr) by algebraic method.

Answer 1

Answer:

$p(q + r) = (pq) + (pr) \\ pq + pr = pq + pr \\ pq - pq = pr - pr \\ 0 = 0$

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Answer 2

p(q+r)=(pq)+(pr)

given the formula,

p(q+r)= (pq)+(pr)

pq+pr=pq+pr.

=0

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