Math, asked by asadbhai2, 2 months ago

prove palleogram are base between same parallels are equal in area​

Answers

Answered by AujlaSaab09
1

Hope its help you..........

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Answered by ItzzHeartlessBoy
2

Answer:

what will be the relation between the areas of these two parallelograms?

theorem: parallelograms on the same base and between the same parallels are equal in area.

proof: consider the figure presented above. can you see that

δ

b

c

e

and

δ

a

d

f

will be congruent? this is easy to show. we have:

bc = ad (opposite sides of a parallelogram are equal)

b

c

e

=

a

d

f

(corresponding angles)

b

e

c

=

a

f

d

(corresponding angles)

by the asa criterion, the two triangles are congruent, which means that their areas are equal. now,

area(abcd) = area(abed) + area(

δ

b

c

e

)

similarly,

area(abef) = area(abed) + area(

δ

a

d

f

)

clearly,

area(abcd) = area(abef)

this completes the proof.

next, consider a parallelogram abcd and a rectangle abef on the same base and between the same parallels:

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