prove perimeter of square is less than that of an equivalent parallelogram on same base
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HEYA USER...
Let PQCB be a square and ABCD be a parallelogram (please have a close look at the figure).
If you look at the figure you can see that AB and CD hypotenuses which are certainly greater in length than PB and QC. So the perimeter of square PQCB is less than that of parallelogram ABCD on same base.
Hence proved.
THANK YOU
HOPE IT HELPS..
Let PQCB be a square and ABCD be a parallelogram (please have a close look at the figure).
If you look at the figure you can see that AB and CD hypotenuses which are certainly greater in length than PB and QC. So the perimeter of square PQCB is less than that of parallelogram ABCD on same base.
Hence proved.
THANK YOU
HOPE IT HELPS..
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