Question

Prove plese
Plese what is the answer
To ​

Answer 1

$\sf \Large Solution!!$

$\sf \large Given:$

$\sf \to AD=BC$

$\sf \to \angle DAB=\angle CBA$

$\sf \large To\;prove:$

$\sf \to BD=AC$

$\sf \large So,$

$\sf In\;\Delta ABD\;and\;\Delta BAC,$

$\sf \to AD=BC\quad (Given)$

$\sf \to \angle DAB=\angle CBA\quad (Given)$

$\sf \to AB=BA\quad (Common)$

$\sf By\;SAS,$

$\sf \Delta ABD\cong \Delta BAC$

$\sf \therefore BD=AC$

$\sf Hence,\;proved.$