prove pressure is equal to hdg
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Answered by
17
Hi friend,
we know that pressure (p)=force (F)/area(A) now force=mass(m) x acceleration due to gravity(g) thus we get p = mg/A...... (1) but we know that density(d)=mass(m)/volume(v) or, mass(m)= density(d) x volume(v) now putting value of m in (1) we get, p=d x v x g / A OR, P=d x g x A x h / A [because we know volume (v)= area(A) xheight(h) ] the A get crossed out from numerator and denominator thus we get P=hdg
HENCE, PROVED..
HOPE THIS HELPS YOU:-))
we know that pressure (p)=force (F)/area(A) now force=mass(m) x acceleration due to gravity(g) thus we get p = mg/A...... (1) but we know that density(d)=mass(m)/volume(v) or, mass(m)= density(d) x volume(v) now putting value of m in (1) we get, p=d x v x g / A OR, P=d x g x A x h / A [because we know volume (v)= area(A) xheight(h) ] the A get crossed out from numerator and denominator thus we get P=hdg
HENCE, PROVED..
HOPE THIS HELPS YOU:-))
Answered by
19
Pressure = Force / Area
= mg / A
= Vdg / A ………[∵ Mass = Volume × Density]
= Ahdg / A ………[∵ Volume = Area × Length]
= hdg
∴ Pressure is equal to hdg
= mg / A
= Vdg / A ………[∵ Mass = Volume × Density]
= Ahdg / A ………[∵ Volume = Area × Length]
= hdg
∴ Pressure is equal to hdg
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