Math, asked by pasy, 1 year ago

prove prove root 3 + root 5 is irrational ​

Answers

Answered by kajalbanwala
64

this is your answer,...........

Attachments:

zainaazfar100: this is wrong. Because when you squared both sides, you're supposed to whole square it as (√3+√5)^2
DPRO: So messed up
varun5511: This is wrong
Answered by Srijan345
30

ANSWER:

( \sqrt{5}  +  \sqrt{3} ) ^{2 }   = {x}^{2}  \\ 5 + 2 \sqrt{15}  + 3 =  {x }^{2}  \\ 2 \sqrt{15}  + 8 =  {x}^{2}  \\ 2 \sqrt{15}  =  {x}^{2}  - 8 \\  \sqrt{15}  =   \frac{ {x }^{2}  - 8}{2}

As x is rational number.

 \frac{ {x}^{2}  - 8}{2} Is also rational number.

But  \sqrt{15} Is a irrational number.

We get rational number = Irrational number

Which is a contradiction.

Our assumption x is rational is wrong.

 \sqrt{5}  +  \sqrt{3} Is irrational number.

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