prove Pythagoras theoram
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base + height = hypotenuse
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Explanation:
Pythagoras Theorem Proof
Given: A right-angled triangle ABC.
To Prove- AC2 = AB2 + BC2
Proof: First, we have to drop a perpendicular BD onto the side AC
We know, △ADB ~ △ABC
Therefore, ADAB=ABAC (Condition for similarity)
Or, AB2 = AD × AC ……………………………..……..(1)
Also, △BDC ~△ABC
Therefore, CDBC=BCAC (Condition for similarity)
Or, BC2= CD × AC ……………………………………..(2)
Adding the equations (1) and (2) we get,
AB2 + BC2 = AD × AC + CD × AC
AB2 + BC2 = AC (AD + CD)
Since, AD + CD = AC
Therefore, AC2 = AB2 + BC2
Hence, the Pythagorean thoerem is proved.
Note: Pythagorean theorem is only applicable to Right-Angled triangle.
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