Question

prove Pythagoras theorem by taking PQR
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Answer 1

In a right triangle the area of the square on the hypotenuse is equal to the sum of the areas of the squares of its remaining two sides. In the adjoining figure, ∆ PQR is a right angled triangle where QR is its hypotenuse and PR > PQ. Square on QR is QRBA, square on PQ is PQST and the square on PR is PRUV.