prove pythagoras theorem ( CLASS 10) ..
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In Right angle triangle , the square of hypotenuse is equal to the square of sum of other two sides
Given: A right-angled triangle ABC, right-angled at B.
To Prove- AC² = AB² + BC²
Construction: Draw a perpendicular BD meeting AC at D.
Pythagoras theorem Proof
Proof:
We know, △ADB ~ △ABC
Therefore, ADAB=ABAC (corresponding sides of similar triangles)
Or, AB² = AD × AC ……………………………..……..(1)
Also, △BDC ~△ABC
Therefore, CDBC=BCAC (corresponding sides of similar triangles)
Or, BC²= CD × AC ……………………………………..(2)
Adding the equations (1) and (2) we get,
AB²+ BC²= AD × AC + CD × AC
AB² + BC² = AC (AD + CD)
Since, AD + CD = AC
Therefore, AC² = AB² + BC²
Hence, the Pythagorean theorem is proved.
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