Question

prove Pythagoras theorem converse​

Answer 1

$<b> hlo frnd here is ur answer$

Converse of Pythagoras Theorem

“ What is Pythagoras Theorem ?

As in the diagram, ABC is a right-angled triangle

with right angle at C, then

a2 + b2 = c2

The converse of Pythagoras Theorem is:

If

a2 + b2 = c2 holds

then

DABC is a right angled triangle with

right angle at C.

How to prove The converse of Pythagoras Theorem ?

Now construct another triangle as follows :

EF = BC = a

ÐF is a right angle.

FD = CA = b

In DDEF,

By Pythagoras Theorem,

……..(2)

By (1), the given,

Theorefore, AB = DE

But by construction, BC = EF

and CA = FD

D ABC @ D DEF (S.S.S.)

hope helps mark as brainliest plz

Answer 2

GIven a ΔABC, with BC = a, AC = b and AB = c. Also given, c2 = a2 + b2 --- (1) Now construct a right angled ΔDEF, with sides EF = BC = a, AC = DF = b. Let DE = d and ∠EFD = 900. SInce, ΔDEF is a right angled triangle, we can use Pythagoras theorem, ⇒ d2 = a2 + b2 But by (1), c2 = a2 + b2 Therefore, c = d i.e. AB = DE Thus, by construction , By SSS test, ΔABC ≃ ΔDEF Thus, ΔABC is a right angled triangle with ∠ACB = 900.