Prove question help!!!Number 22
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Solution,
Given: BGA and AEC are straight lines.
Construction: GF, FE and FD lines are constructed.
Now,
1) BDFG, DFEC, AGFE are cyclic quadrilateral.
2) angle.FDC = angle.BGF [ The external angle of a cyclic quadrilateral is equal to opposite internal angle]
3) angle.AGF = angle.FEC [The external angle of a cyclic quadrilateral is equal to opposite internal angle]
4) angle.BGF+angle.FEC = 180 [ Sum of two opposite interior angle is 180]
or, angle.FDC+angle.AGF=180
5)AGB is a straight line. [Because angle.FDC+angle.AGF=180]
It is a Nepali SEE question. Hope it helped you a lot.
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