Question

prove
question in attachment..​

Answer 1

Step-by-step explanation:

cos(90° - x) = sin x

cot(90° - x) = tan x

$\frac{ \cos(x) \cos(90 - x) }{ \cot(90 - x) } \\ = \frac{ \cos(x) \sin(x) }{ \tan(x) } \\ = \frac{ \cos(x) \sin(x) }{ \frac{ \sin(x) }{ \cos(x) } } \\ = \cos(x) \sin(x) \times \frac{ \cos(x) }{ \sin(x) } \\ = \cos(x) \times \cos(x) = { \cos }^{2} x$