Prove R = work/Mole × temperature
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Where,
R is the universal gas constant =8.314Jmol−1K−1
n = Number of moles = 1
T = Standard temperature = 273 K
P = Standard pressure = 1 atm =1.013×105Nm−2
∴V=nRT/P
=1×8.314×273/(1.013×105)
=0.0224m3
=22.4 litres
Hence, the molar volume of a gas at STP is 22.4 litres.
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