prove r1+r2=alpha (from deviation of light from two mirrors)
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hello mate the ans is
A=r 1 +r 2 ,r 1
=r 2
=r
A=2r
(i=e)
δ=i+e−(r 1 +r 2 )
δ=2i−2r=2(i−r)
δ
min
= Whose ray is parallel to base.
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