Prove resistanceof a conductor is inversely proportional to the square of the radius of counductor and square of the diameter
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Cross sectional area is the area of the end of the wire (assuming a perfectly flat right angle cut). So it's proportional to the square of diameter. Resistance is inversely proportional to cross sectional area. So if the diameter is halved the cross-sectional area is quartered and the resistance is quadrupled.
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Answer:
Prove resistance of a conductor is inversely proportional to (i) the square
of the radius of conductor and (ii) the square of the diameter of the
conductor?
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