prove rhe trigonometric identity : (1+tan^2 0) (1+sin 0) (1-sin 0) =1
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2
Step-by-step explanation:
(1+tan²A)(1-sin²A). { bcz (a+b)(a-b) = a²-b²}
=→(sec²A)(cos²A)
=→(1/cos²A)(cos²A)
=→1
=RHS
Hence proved.
Answered by
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Answer:
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