Question

Prove root 10 is irrational number by the me
thod of contradiction

Answer 1

Answer:

Let's assume that 3√10 is rational no.

So,it can be expressed in the form of a/b form where a and b are integers.

So: 3√10=a/b

√10=a/3b

Since a and b are integers ,so a/3b is rational no. which implies that 3√10 is also rational no.

But it contradicts the fact that √10 is an irrational no.

Therefore our assumption is wrong, 3√10 is an irrational no.