prove root 3 + root 5 is irrational
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Ans:- Let √3+√5 be a rational number.
A rational number can be written in the form of p/q where p,q are integers.
=>√3+√5 = p/q
=>√3 = p/q-√5
Squaring on both sides,
=>(√3)² = (p/q-√5)²
=>3 = p²/q²+√5²-2(p/q)(√5)
=>√5×2p/q = p²/q²+5-3
=> √5 = (p²+2q²)/q² × q/2p
=>√5 = (p²+2q²)/2pq
p,q are integers then (p²+2q²)/2pq is a rational number. Then √5 is also a rational number.
But this contradicts the fact that √5 is an irrational number. So,our supposition is false.
Therefore, √3+√5 is an irrational number. (Ans)
☆i hope its help☆
given by:-
Ans:- Let √3+√5 be a rational number.
A rational number can be written in the form of p/q where p,q are integers.
=>√3+√5 = p/q
=>√3 = p/q-√5
Squaring on both sides,
=>(√3)² = (p/q-√5)²
=>3 = p²/q²+√5²-2(p/q)(√5)
=>√5×2p/q = p²/q²+5-3
=> √5 = (p²+2q²)/q² × q/2p
=>√5 = (p²+2q²)/2pq
p,q are integers then (p²+2q²)/2pq is a rational number. Then √5 is also a rational number.
But this contradicts the fact that √5 is an irrational number. So,our supposition is false.
Therefore, √3+√5 is an irrational number. (Ans)
☆i hope its help☆
Answered by
3
root5 is irrational no.Addition with irrational no. is also irrational .So,3+root5 is irrational
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