Prove root 5 as a irrational no.
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hii...
here's ur solution dude.!
let us assume ,to the contrary that root 5 is rational .
therefore root 5 =a/b.....(a &b are co prime)
root 5 ×b =a
squaring on both side ,
5b२=a२..........considered as equation1
therefore 5 is a factor of a२
therefore 5 is divided by a२........considered as eq2
now, a/b =c......(c is any constant)
therefore a२=25c२
put in eq. 1
a२=25c२
5b२=a२
5b२=25c२
b२=5c२
ie(5c२=b२)
therefore b२ is divisible by 5 and b is also divisible by 5
therefore a and b have atleast 5 as a common factor .
but this contradiction that a and b are co prime .
hence root 5 is not rational no.
hence root is irrational no.
hence proved!!!
hope it helps uh:)
here's ur solution dude.!
let us assume ,to the contrary that root 5 is rational .
therefore root 5 =a/b.....(a &b are co prime)
root 5 ×b =a
squaring on both side ,
5b२=a२..........considered as equation1
therefore 5 is a factor of a२
therefore 5 is divided by a२........considered as eq2
now, a/b =c......(c is any constant)
therefore a२=25c२
put in eq. 1
a२=25c२
5b२=a२
5b२=25c२
b२=5c२
ie(5c२=b२)
therefore b२ is divisible by 5 and b is also divisible by 5
therefore a and b have atleast 5 as a common factor .
but this contradiction that a and b are co prime .
hence root 5 is not rational no.
hence root is irrational no.
hence proved!!!
hope it helps uh:)
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