Math, asked by Ravishkumar11, 1 year ago

Prove root 5 as a irrational no.


dilpreet10: y 1.3 khol laaa appe lgg ju math ch swan te jaaa self study tee
Ravishkumar11: sorry

Answers

Answered by ambikaahuja30
0
Here's the answer. I hope this helps. Mark it as the brainliest, if you want to.
Attachments:
Answered by Saakshi01
1
hii...
here's ur solution dude.!
let us assume ,to the contrary that root 5 is rational .
therefore root 5 =a/b.....(a &b are co prime)

root 5 ×b =a
squaring on both side ,
5b२=a२..........considered as equation1
therefore 5 is a factor of a२
therefore 5 is divided by a२........considered as eq2

now, a/b =c......(c is any constant)
therefore a२=25c२

put in eq. 1

a२=25c२
5b२=a२
5b२=25c२
b२=5c२

ie(5c२=b२)

therefore b२ is divisible by 5 and b is also divisible by 5
therefore a and b have atleast 5 as a common factor .
but this contradiction that a and b are co prime .
hence root 5 is not rational no.
hence root is irrational no.
hence proved!!!


hope it helps uh:)

Saakshi01: hey... if ur satisfied then mark as brainliest:)
Saakshi01: ..
dilpreet10: kiii
dilpreet10: bolllyaaaa
Ravishkumar11: Thanks
Similar questions