prove root 5 irrational......... please urgent
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Let us assume on the contrary that √5 is rational. So there exists two co prime positive integers a and b.
So, √5=a/b
√5b= a
Squaring on both sides
5b^2 =a^2
So a divides 5b^2 -----------》1
a=5c for some integer c.
Squaring on both sides,
a^2 =25c^2
Substituting a^2 value
5b^2=25c^2
b^2=5c^2 ------------》2
So b divides 5c^2.
So from 1 and 2 our assumption is wrong.Since we assumed that the two integers a and b has only a common factor 1. So √5 is irrational.
So, √5=a/b
√5b= a
Squaring on both sides
5b^2 =a^2
So a divides 5b^2 -----------》1
a=5c for some integer c.
Squaring on both sides,
a^2 =25c^2
Substituting a^2 value
5b^2=25c^2
b^2=5c^2 ------------》2
So b divides 5c^2.
So from 1 and 2 our assumption is wrong.Since we assumed that the two integers a and b has only a common factor 1. So √5 is irrational.
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