Question

Prove root7-2 is irrational

Answer 1

Answer:

Step-by-step explanation:

Hi friend, Here's the required answer:-

Let us assume that 2/√7 is rational number.

2/√7= 2/√7 × (√7/√7)= 2√7/7. ( Rationalising)

Now, 2√7/7 = p/q ( as rational no. can be written in the form of p/q=)

2√7= 7p/q

√7= 7p/2q

Here LHS is irrational but RHS is rational.

This contradicts the statement.

Our assumption is wrong.

2/ √7 is an irrational number.

Hope this helps you...Budd!

Answer 2

Step-by-step explanation:

let √7- 2 to be equal to a/b where a and b are rational numbers and does not have any other Common Factor other than one

√7-2=a/b

√7=a/b+2

we know that A and B are positive integers and a /b+ 2 is rational no but since √7 is irrational so it contradicts hens √7- 2 is irrational

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